[Rcpp-devel] Deep copying a matrix
Douglas Bates
bates at stat.wisc.edu
Thu Jul 14 18:46:21 CEST 2011
The way to guarantee a deep copy is to use Rcpp::clone(). In general
I recommend using a const qualifier on any vectors or arrays
constructed directly from the function arguments. If they need to be
coerced to another storage type they will end up being a deep copy of
the original but to preserve the functional programming semantics you
should regard any arguments passed to C++ function from R as
read-only.
I would rewrite your code fragment as
const Rcpp::NumericMatrix m_source(origin);
Rcpp::NumericMatrix m_copy = Rcpp::clone(m_source);
On Thu, Jul 14, 2011 at 11:36 AM, Etienne B. Racine <etiennebr at gmail.com> wrote:
> Hi list,
>
> I'm struggling with the copy of my parameters. If I understand correctly, if
> you ship an int matrix to the function, you'll get a deep copy. However if
> it's a numeric matrix, then there's no copy and you get a matrix pointing on
> your R matrix. That's funny when you try to debug as one might work and the
> other not.
>
> Here's an illustration
> library(Rcpp); library(inline)
>
> f1 <- cxxfunction(signature(origin="numeric"), body = "
> Rcpp::NumericMatrix m_source(origin);
> m_source(0,0) = 0;
> cout << origin << endl << m_source << endl ; ",
> include = "using namespace std;",
> plugin="Rcpp")
>
> m <- matrix(1:4,2,2)
> x <- f1(m)
>
> #0x9c7fe18
> #0xb416a1a8 # different
> m
> # [,1] [,2]
> #[1,] 1 3
> #[2,] 2 4
> m <- matrix(1:4/2,2,2)
> x <- f1(m)
> #0xb416a090
> #0xb416a090 # no different
> m
> # [,1] [,2]
> #[1,] 0 1.5
> #[2,] 1 2.0
>
> Now, what I'd like is to have a (deep) copy of that matrix, whatever the
> type. I've tried
> Rcpp::NumericMatrix m_copy = m_source; // of course it did not work, but
> never know with vectorisation ;-)
> sdt::copy(m_source.begin(), m_source.end(), std::back_inserter(m_copy)) //
> nope
>
> The closer I got was with
> f2 <- cxxfunction(signature(origin="numeric"), body = "
> Rcpp::NumericMatrix m_source(origin);
> Rcpp::NumericMatrix m_copy;
> Rcpp::NumericMatrix::iterator itr;
> cout << m_copy << endl << endl;
> m_source(0,0) = 0;
> for(itr = m_source.begin(); itr != m_source.end(); ++itr)
> m_copy.push_back(*itr);
> m_copy[3] = 1; // matrix structure is lost or never
> existed;
> cout << origin << endl << m_source << endl << m_copy ;
> return wrap(m_copy);",
> include = "using namespace std;",
> plugin="Rcpp", verbose= FALSE)
>
> Main drawback is that I loose the matrix structure. I'm sure there's a
> correct way to do this, but I couldn't find it.
>
> Etienne
>
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