[Rcpp-devel] Deep copying a matrix
Etienne B. Racine
etiennebr at gmail.com
Thu Jul 14 18:36:48 CEST 2011
Hi list,
I'm struggling with the copy of my parameters. If I understand correctly, if
you ship an int matrix to the function, you'll get a deep copy. However if
it's a numeric matrix, then there's no copy and you get a matrix pointing on
your R matrix. That's funny when you try to debug as one might work and the
other not.
Here's an illustration
library(Rcpp); library(inline)
f1 <- cxxfunction(signature(origin="numeric"), body = "
Rcpp::NumericMatrix m_source(origin);
m_source(0,0) = 0;
cout << origin << endl << m_source << endl ; ",
include = "using namespace std;",
plugin="Rcpp")
m <- matrix(1:4,2,2)
x <- f1(m)
#0x9c7fe18
#0xb416a1a8 # differentm# [,1] [,2]
#[1,] 1 3
#[2,] 2 4m <- matrix(1:4/2,2,2)x <- f1(m)#0xb416a090
#0xb416a090 # no differentm# [,1] [,2]
#[1,] 0 1.5
#[2,] 1 2.0
Now, what I'd like is to have a (deep) copy of that matrix, whatever the
type. I've tried
Rcpp::NumericMatrix m_copy = m_source; // of course it did not work, but
never know with vectorisation ;-)
sdt::copy(m_source.begin(), m_source.end(), std::back_inserter(m_copy)) //
nope
The closer I got was with
f2 <- cxxfunction(signature(origin="numeric"), body = "
Rcpp::NumericMatrix m_source(origin);
Rcpp::NumericMatrix m_copy;
Rcpp::NumericMatrix::iterator itr;
cout << m_copy << endl << endl;
m_source(0,0) = 0;
for(itr = m_source.begin(); itr != m_source.end(); ++itr)
m_copy.push_back(*itr);
m_copy[3] = 1; // matrix structure is lost or never
existed;
cout << origin << endl << m_source << endl << m_copy ;
return wrap(m_copy);",
include = "using namespace std;",
plugin="Rcpp", verbose= FALSE)
Main drawback is that I loose the matrix structure. I'm sure there's a
correct way to do this, but I couldn't find it.
Etienne
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