[Rcpp-devel] Strange behaviro using Rcpp sugar with NumericMatrix
Roland Denis
roland.denis at math.univ-lyon1.fr
Wed Mar 15 14:17:38 CET 2017
Hello,
while comparing the performance between pure R and different other
syntaxes that mix R and Rcpp, I found out a strange behavior when using
Rcpp sugar on NumericMatrix. As far as I understand Rcpp (I'm a newbie
in R and Rcpp), syntactic sugar is designed for NumericVector, but since
NumericMatrix seems to be seen like an augmented NumericVector, I've
supposed this works on NumericMatrix too (and, in fact, it compiles).
Here is a minimal example :
library(Rcpp)
cppFunction("
NumericMatrix scaleSugar( NumericMatrix A, double k )
{
return k*A;
}
")
A <- diag(3)
B = scaleSugar(A, 2)
Displaying A and B returns :
> A
[,1] [,2] [,3]
[1,] 2 0 0
[2,] 0 2 0
[3,] 0 0 2
> B
[,1] [,2] [,3]
[1,] 2 0 0
[2,] 0 2 0
[3,] 0 0 2
As you see, the matrix A seems to be multiplied in-place and returned.
Creating the returned matrix before the multiplication doesn't change
the result :
library(Rcpp)
cppFunction("
NumericMatrix scaleSugar( NumericMatrix A, double k )
{
NumericMatrix R( A.nrow(), A.ncol());
R = k*A;
return R;
}
")
A <- diag(3)
B = scaleSugar(A, 2)
> A
[,1] [,2] [,3]
[1,] 2 0 0
[2,] 0 2 0
[3,] 0 0 2
However, copying A into R before the scaling works :
library(Rcpp)
cppFunction("
NumericMatrix scaleSugar( NumericMatrix A, double k )
{
NumericMatrix R( A.nrow(), A.ncol(), A.begin());
return k*R;
}
")
A <- diag(3)
B = scaleSugar(A, 2)
> A
[,1] [,2] [,3]
[1,] 1 0 0
[2,] 0 1 0
[3,] 0 0 1
and, *more surprisingly*, reversing the multiplication operand's order
works too :
library(Rcpp)
cppFunction("
NumericMatrix scaleSugar( NumericMatrix A, double k )
{
return A*k;
}
")
A <- diag(3)
B = scaleSugar(A, 2)
> A
[,1] [,2] [,3]
[1,] 1 0 0
[2,] 0 1 0
[3,] 0 0 1
Are Rcpp sugars supposed to work with NumericMatrix ?
Many thanks,
--
Roland
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