[Rcpp-devel] How to create list of list without known structure

[Romain Francois]

Le 6 mai 2014 à 09:35, Florian Burkart <florian.burkart at gmail.com> a écrit :

> Hi,
> 
> I have been creating lists of lists with 
> 
> return Rcpp::List::create(Rcpp::Named("vec") = someVector,
>                           Rcpp::Named("lst") = someList,
>                           Rcpp::Named("vec2") = someOtherVector);
> 
> or to follow Romain:
> 
> using namespace Rcpp ;
> return List::create( 
>    _["vec"]  = someVector, 
>    _["lst"]  = someList, 
>    _["vec2"] = someOtherVector
>  ) ;
> 
> But how do I convert the following into a list of lists?
> 
> std::vector<std::string> m_column_headers;
> std::vector<std::vector<OptDouble> > m_vectors_of_values;

You probably just need to know about .names() =, i.e. something like this should do: 

List values = wrap(m_vectors_of_values) ;
values.names()  = m_column_headers ;

FWIW, in Rcpp11, you could use structure, e.g. :

List values = structure( m_vectors_of_values, _["names"] = m_column_headers ) ;

Romain