[Rcpp-devel] Returning a named (and classed?) list from an RcppExport SEXP function
Dirk Eddelbuettel
edd at debian.org
Fri Mar 12 17:47:15 CET 2010
Hi Doug,
Welcome! We're honoured to have you here. And glad you picked the list.
On 12 March 2010 at 10:14, Douglas Bates wrote:
| I have looked at your (i.e. Dirk and Roman's) submitted Rjournal
| article on Rcpp and decided that I should take the plunge.
|
| To get my feet wet I am starting with a relatively simple example
| interfacing to (God help us) 1960's style Fortran written by Mike
| Powell and incorporated in the minqa package.
|
| The value to be returned is a named list of heterogeneous values. I
| can see how to construct such a list in the classic Rcpp API using a
| RcppResultSet object but I don't know the best way to accomplish this
| in the more modern Rcpp namespace. Can someone point me in the right
| direction? Also, is there a convenient idiom for attaching an S3
| class name to a list to be returned?
Yes. See eg the examples I put on my blog, eg inside of RcppArmadillo we
simply do (including actual fastLm source here modulu two ifdefs dealing with
older versions -- which means you need Armadillo 0.9.0 or later)
#include <RcppArmadillo.h>
extern "C" SEXP fastLm(SEXP ys, SEXP Xs) {
Rcpp::NumericVector yr(ys); // creates Rcpp vector from SEXP
Rcpp::NumericMatrix Xr(Xs); // creates Rcpp matrix from SEXP
int n = Xr.nrow(), k = Xr.ncol();
arma::mat X(Xr.begin(), n, k, false); // reuses memory and avoids extra copy
arma::colvec y(yr.begin(), yr.size(), false);
arma::colvec coef = solve(X, y); // fit model y ~ X
arma::colvec resid = y - X*coef; // residuals
double sig2 = arma::as_scalar( trans(resid)*resid/(n-k) );
// std.error of estimate
arma::colvec stderrest = sqrt( sig2 * diagvec( arma::inv(arma::trans(X)*X)) );
Rcpp::Pairlist res(Rcpp::Named( "coefficients", coef),
Rcpp::Named( "stderr", stderrest));
return res;
}
[ By the way, I still think I should try to implement all four of your "how
to do lm" solutions from the older R News / R Journal piece in Armadillo one
day :-) And see what the timing impacts would be. ]
That works "on the fly" with Pairlist and named. We also have Rcpp::List
examples, but AFAICR you need to 'predeclare' how long your list is and the
set each element. The 200+ unit tests will have examples. Better docs will
appear one day...
| An unrelated question -- has anyone looked at accessing S4 classed
| objects in Rcpp? I have had considerable experience with S4 classes
| and objects and could keep such a project in mind as I begin to
| explore Rcpp.
I'd be happy to go there (time permitting) but very gently as I am still much
more firmly in S3 land. Romain may be more eager :)
| Yet another question, if i may. Does coercion take place in
| constructing an object like
|
| Rcpp::NumericVector aa(a);
|
| where a is an SEXP, say an SEXP argument to a C++ function, where I
| accidentally passed an integer vector instead of a double vector? If
Very much so. Again, see my blog and the RcppVectorExample code. Int in,
Double out. All magic hidden.
And of course you can just try it:
R> library(RcppExamples)
Loading required package: Rcpp
R> RcppVectorExample(c(1,4,9), api="new")
$result
[1] 1 2 3
$original
[1] 1 4 9
R> RcppVectorExample(c(2,5,10), api="new")
$result
[1] 1.414 2.236 3.162
$original
[1] 2 5 10
R>
At this level, behaviour is the same with 'classic' API but we know of at
least one case where 'classic' doesn't cast a Matrix right and 'new' does.
| so, what happens if there is no coercion? Are the contents of the
| SEXP copied to newly allocated storage or not?
It depends. In the new API we do fewer copies.
| The reason that I ask is because there are some places in the lme4
| code where I want to make sure that I have a pointer to the contents
| of the original vector because I am want to change the contents
| without copying.
I think we do that. If you look at the vignette and the timing example -- but
using pointer accessors (eg double *x = foo.begin()) and pointer ops (eg x++)
we get essentially the same speed as pure and ugly C code. Because we do
away with the copy, and the operator[], for purest speed.
Hope that answer the first batch of questions. Keep'em coming!
Dirk
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