[datatable-help] lapply without anonymous function

[Eduard Antonyan]

But I guess your second attempt should have worked - submit a bug request
imo.
 On Nov 11, 2013 7:40 AM, "Eduard Antonyan" <eduard.antonyan at gmail.com>
wrote:

> I think your last attempt's failure is a bug of the internal cedta
> function, but note that if it did work, it'd be more symbols to type than
> the anonymous function option :)
>  On Nov 10, 2013 1:39 PM, "G See" <gsee000 at gmail.com> wrote:
>
>> Hi,
>>
>> I have a list of data.tables and I am trying to extract a subset from
>> each of them.  I can achieve what I want with this:
>>
>> > L <- list(data.table(BOD), data.table(BOD))
>> > lapply(L, function(x) x[Time==3L])
>> [[1]]
>>    Time demand
>> 1:    3     19
>>
>> [[2]]
>>    Time demand
>> 1:    3     19
>>
>> However, I'd rather not type have to create an anonymous function.  I
>> tried the below, but `[.data.frame` is being dispatched.
>>
>> > lapply(L, "[", Time==3L)
>> Error in `[.data.frame`(x, i) : object 'Time' not found
>>
>> Even if I am explicit, `[.data.table` does not get dispatched:
>>
>> > lapply(L, data.table:::`[.data.table`, Time==3L)
>> Error in `[.data.frame`(x, i) : object 'Time' not found
>>
>> I'm guessing this is due to where evaluation takes place.  Is there an
>> alternate syntax I should use?
>>
>> Thanks,
>> Garrett
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>>
>
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