[datatable-help] Sum first 3 non zero elements of row
José Verhoeven
jose at memo2.nl
Tue May 21 15:38:50 CEST 2013
Thank you, it really helped me out! Didn't need the data.table like you
proposed.
2013/5/21 Gabor Grothendieck <ggrothendieck at gmail.com>
> On Tue, May 21, 2013 at 5:10 AM, JNV <jose at memo2.nl> wrote:
> > Hi there,
> > I've got this matrix D with, say 10 rows and 20 columns. For each row I
> want
> > to sum the first 3 non zero elements and put them in a vector z.
> >
> > So if the first row D[1,] is
> > 0 3 5 0 8 9 3 2 4 0
> >
> > then I want z
> > z<-D[1,2]+D[1,3]+D[1,5]
> >
> > But if there are less than 3 non zero elements, those should be summed.
> If
> > there are no non zero elements, the result must be zero.
> >
> > So if the first row D[1,] is
> > 0 0 3 0 1 0 0 0 0 0
> >
> > then I want z
> > z<-D[1,3]+D[1,5]
> >
>
> Here is a matrix, D, with those two rows The t(apply(...)) replaces
> the first non-zero element in each row with 1, the 2nd with 2, etc.
> (It puts garbage into the elements that are 0.) We then convert
> this to T/F according to whether each element less than or equal to 3
> or not and multiply by the original data which both zaps the garbage
> in the zero positions and zaps those positions which are a 4th or more
> non-zero in each row. This multiplication also inserts the correct
> values into the good positions. Finally we sum the rows using what is
> left:
>
> > D <- matrix( c(0, 0, 3, 0, 5, 3, 0, 0, 8, 1, 9, 0, 3,
> + 0, 2, 0, 4, 0, 0, 0), 2)
> >
> > D
> [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
> [1,] 0 3 5 0 8 9 3 2 4 0
> [2,] 0 0 3 0 1 0 0 0 0 0
> >
> > as.data.table(D)[, rowSums((t(apply(.SD > 0, 1, cumsum)) <= 3) * .SD)]
> [1] 16 4
>
> Not sure if this really benefits from data.table as we could have
> written this without data.table:
>
> > rowSums((t(apply(D > 0, 1, cumsum)) <= 3) * D)
> [1] 16 4
>
>
> --
> Statistics & Software Consulting
> GKX Group, GKX Associates Inc.
> tel: 1-877-GKX-GROUP
> email: ggrothendieck at gmail.com
>
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