[datatable-help] A new package multitable (data.list) remind me of a long existing feature request #202 and discussion thread
Matthew Dowle
mdowle at mdowle.plus.com
Thu Oct 6 09:15:40 CEST 2011
Indeed. Or columns 11 and 12 of BED files (genomics). Near on the agenda
is a fast file loader straight into data.table and list columns
(dual-delimited files such as BED).
I don't believe SQL has an analogous concept to list columns? To achieve
that people may be using comma delimited strings in varchar columns, I
guess.
On Wed, 2011-10-05 at 16:19 -0500, Branson Owen wrote:
> Thank you very, very much Matthew. I think this is a very valuable (at
> least to me), and unique feature for more powerful calculation. A very
> useful application I can immediately think of is for options chains
> and order book modeling. It's much easier to track and model the whole
> option chains or order book for each time stamp or symbol, and also
> save a lot of replicating time stamps and symbols.
>
> 2011/10/4 Matthew Dowle <mdowle at mdowle.plus.com>
> On Sun, 2011-10-02 at 15:14 +0800, Branson Owen wrote:
>
> > Oh, sorry, I was testing the syntax like:
> >
> > DT = data.table(A = 1:2, B = list('a', 2i))
> >
> > It didn't work, and I though this feature has not been
> implemented.
> > Thank you for pointing it out with a good example.
>
>
> Natural to assume that should work. Now in 1.6.7 :
>
> o data.table() now accepts list columns directly rather than
> needing to add list columns to an existing data.table;
> e.g.,
>
> DT = data.table(x=1:3,y=list(4:6,3.14,matrix(1:12,3)))
>
> Thanks to Branson Owen for reminding.
>
> Accordingly, one item has been added to FAQ 2.17
> (differences
> between data.frame and data.table) :
> "data.frame(list(1:2,"k",1:4))
> creates 3 columns, data.table creates one list column"
>
> As before, list columns can be created via grouping; e.g.,
>
> DT = data.table(x=c(1,1,2,2,2,3,3),y=1:7)
> DT2 = DT[,list(list(unique(y))),by=x]
> DT2
> x V1
> [1,] 1 1, 2
> [2,] 2 3, 4, 5
> [3,] 3 6, 7
>
> and list columns can be grouped; e.g.,
>
> DT2[,sum(unlist(V1)),by=list(x%%2)]
> x V1
> [1,] 1 16
> [2,] 0 12
>
>
>
>
>
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