[datatable-help] Basic join question
Matthew Dowle
mdowle at mdowle.plus.com
Wed Aug 17 12:53:17 CEST 2011
Yang,
Since you also asked on SO, suggest we answer there (after your edit please)
:
http://stackoverflow.com/questions/7090621/how-to-do-a-basic-left-outer-join-with-data-table-in-r
Matthew
"Yang Zhang" <yanghatespam at gmail.com> wrote in message
news:CAKxBDU_o3i_+xujsCa0CmukDizctx6fnzbidOYZW9Co9w9iTvw at mail.gmail.com...
> How do I do the equivalent to the following?
>
> with dt as (select 1 as a, 0 as b union select 1, 0 union select 2, 0
> union select 2, 1 union select 3, 1 union select 3, 1),
> above as (select a, b from dt where b > .5),
> below as (select a, b from dt where b < .5)
> select above.a, count(below.a) from above left outer join below on
> (above.a = below.a) group by above.a;
> a | count
> ---+-------
> 3 | 0
> 2 | 1
> (2 rows)
>
> How do I accomplish the same thing with data.tables? This is what I
> have so far:
>
> DT = data.table(a=as.integer(c(1,1,2,2,3,3)), b=c(0,0,0,1,1,1))
> above = DT[DT$b > .5]
> below = DT[DT$b < .5, list(a=a)]
> key(below) = 'a'
> below[above, list(count=length(a)), by=a]
>
> but this gives me:
>
> a count
> [1,] 2 1
> [2,] NA 1
>
> Thanks in advance for any tips.
>
> --
> Yang Zhang
> http://yz.mit.edu/
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