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<div class="moz-cite-prefix">Hi Niek,<br>
<br>
The variance is computed using the outcome of the seqdur function:
<br>
<br>
<tt>s1 <- seqdef("A-A-B-B-C-C-A-A-A-A")</tt><tt><br>
</tt><tt>x <- seqdur(s1)</tt><tt><br>
</tt><tt>x</tt><tt><br>
</tt><tt><br>
n <- sum(!is.na(x))<br>
</tt><tt>var <- 1/n * sum((x - mean(x, na.rm = TRUE))^2, na.rm
= TRUE)</tt><tt><br>
</tt><tt>var<br>
</tt><br>
Best regards,<br>
Alexis<br>
<br>
Le 23/01/2014 12:23, Niek Frans a écrit :<br>
</div>
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cite="mid:CA+LR1+Ht9DM6K9aqNz-Bt+h=0BW+Vhb445cASLWq_Eb9wh1mTQ@mail.gmail.com"
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<div>Hello everyone,<br>
<br>
</div>
This is probably a very simple question, but I've spend
a couple of hours trying to find the answer without any
luck, so I thought it try it here.<br>
<br>
</div>
I'm trying to explain the Turbulence measure by Elzinga,
but I'm stuck trying to compute the variance of the
state-duration for the sequence. Could anyone explain how
the variance of a sequence is calculated? I know it has
something to do with the sequence length and the
consecutive length of remaining in one state, but I can't
find the exact formula anywhere.<br>
</div>
<br>
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Kind regards,<br>
<br>
<br>
</div>
Niek<br>
</div>
<br>
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