[datatable-help] lapply without anonymous function

[Eduard Antonyan]

I think your last attempt's failure is a bug of the internal cedta
function, but note that if it did work, it'd be more symbols to type than
the anonymous function option :)
 On Nov 10, 2013 1:39 PM, "G See" <gsee000 at gmail.com> wrote:

> Hi,
>
> I have a list of data.tables and I am trying to extract a subset from
> each of them.  I can achieve what I want with this:
>
> > L <- list(data.table(BOD), data.table(BOD))
> > lapply(L, function(x) x[Time==3L])
> [[1]]
>    Time demand
> 1:    3     19
>
> [[2]]
>    Time demand
> 1:    3     19
>
> However, I'd rather not type have to create an anonymous function.  I
> tried the below, but `[.data.frame` is being dispatched.
>
> > lapply(L, "[", Time==3L)
> Error in `[.data.frame`(x, i) : object 'Time' not found
>
> Even if I am explicit, `[.data.table` does not get dispatched:
>
> > lapply(L, data.table:::`[.data.table`, Time==3L)
> Error in `[.data.frame`(x, i) : object 'Time' not found
>
> I'm guessing this is due to where evaluation takes place.  Is there an
> alternate syntax I should use?
>
> Thanks,
> Garrett
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